Math · Problem Solving and Data Analysis

Percentages

Explanation

Percentages represent ratios out of 100100, expressed using the symbol %\%. Calculating with percentages involves converting between fractions, decimals, and relative amounts to solve for totals, changes, or rates.

Core Percentage Calculations

A percentage expresses a fraction of 100100: p%=p100p\% = \frac{p}{100}.

  • Finding the Part: Multiply the total value by the percentage written as a decimal or fraction.

    Example: Find 15%15\% of 80  ⟹  0.15×80=1280 \implies 0.15 \times 80 = 12.

  • Finding the Percentage (Rate): Divide the part by the whole and multiply by 100%100\%.

    Example: 1818 out of 2424 is what percentage?   ⟹  1824=0.75  ⟹  75%\implies \frac{18}{24} = 0.75 \implies 75\%.

  • Finding the Whole (Total): Divide the known part by the percentage written as a decimal.

    Example: If 3030 is 40%40\% of a number x  ⟹  0.40x=30  ⟹  x=300.40=75x \implies 0.40x = 30 \implies x = \frac{30}{0.40} = 75.

Percentage Increase, Decrease, and Change

Percentage change measures the relative growth or decay of a value relative to its original starting amount.

  • Percent Change Formula: Calculate the change as a fraction of the original value:

    Percent Change=New Value−Original ValueOriginal Value×100%\text{Percent Change} = \dfrac{\text{New Value} - \text{Original Value}}{\text{Original Value}} \times 100\%

    Example: A price rises from $50\$50 to $65\$65. Change =65−5050×100%=1550×100%=30% increase= \frac{65 - 50}{50} \times 100\% = \frac{15}{50} \times 100\% = 30\% \text{ increase}.

  • Multiplier for Increase (1+r1 + r): An increase of r%r\% scales the original amount by (1+r)(1 + r).

    Example: A $200\$200 item increased by 8%8\% costs 200×(1+0.08)=200×1.08=$216200 \times (1 + 0.08) = 200 \times 1.08 = \$216.

  • Multiplier for Decrease (1−r1 - r): A discount or decrease of r%r\% scales the original amount by (1−r)(1 - r).

    Example: A $120\$120 jacket discounted by 25%25\% costs 120×(1−0.25)=120×0.75=$90120 \times (1 - 0.25) = 120 \times 0.75 = \$90.

Successive Percentage Changes

When multiple percentage changes occur in sequence, apply multipliers consecutively to the updated values rather than simply adding the percentages together.

  • Sequential Discount/Growth: Multiply the original value by each successive multiplier.

    Example: An item priced at $100\$100 is discounted by 20%20\%, then the new price is discounted by an additional 10%10\%:

    Final Price=100×(1−0.20)×(1−0.10)=100×0.80×0.90=$72\text{Final Price} = 100 \times (1 - 0.20) \times (1 - 0.10) = 100 \times 0.80 \times 0.90 = \$72

    (Note: A 20%20\% discount followed by a 10%10\% discount equals a total 28%28\% discount, not 30%30\%).

Example 1

The expression 0.65x0.65x represents the result of decreasing a positive quantity xx by what percent?
A
35%35\%
B
65%65\%
C
75%75\%
D
135%135\%
Choice A is correct. If xx is decreased by pp percent, the result is x(1−p100)x(1 - \frac{p}{100}). Setting 1−p100=0.651 - \frac{p}{100} = 0.65 gives p100=0.35\frac{p}{100} = 0.35, so p=35p = 35. Choice B is incorrect; it mistakes the coefficient 0.650.65 itself, expressed as a percent, for the percent decrease, rather than subtracting it from 11 first. Choice C is incorrect; it results from computing 1−0.65=0.351 - 0.65 = 0.35 correctly as a decimal but then misreading it as 75%75\%. Choice D is incorrect; it results from adding 0.650.65 to 11 instead of subtracting it, which would represent an increase, not a decrease.

Example 2

The positive number aa is 40%40\% of the sum of the positive numbers bb and cc, and bb is 50%50\% of cc. What percent of bb is aa?
A
60%60\%
B
80%80\%
C
120%120\%
D
150%150\%
Choice C is correct. The first relationship gives a=0.40(b+c)a = 0.40(b + c). The second relationship gives b=0.50cb = 0.50c, so c=2bc = 2b. Substituting, a=0.40(b+2b)=0.40(3b)=1.2ba = 0.40(b + 2b) = 0.40(3b) = 1.2b, so aa is 120%120\% of bb. Choice A is incorrect; it results from substituting c=0.5bc = 0.5b instead of correctly solving b=0.5cb = 0.5c for cc in terms of bb. Choice B is incorrect; it results from using a=0.40(b+c)a = 0.40(b + c) with c=bc = b instead of c=2bc = 2b, ignoring the second relationship entirely. Choice D is incorrect; it results from computing 0.40(b+c)0.40(b + c) with c=3bc = 3b instead of c=2bc = 2b.

Tips for solving

  1. Use single decimal multipliers directly for rapid percent increase and decrease calculations.

    Example: Increase $85\$85 by 12%12\%.

    • Growth multiplier: 1+0.12=1.121 + 0.12 = 1.12

    • Final amount: 85×1.12=$95.2085 \times 1.12 = \$95.20

  2. Use single decimal multipliers directly for rapid percent increase and decrease calculations. 

    Example: A population drops from 500500 to 400400. What is the percent decrease?

    • Change: 500−400=100500 - 400 = 100

    • Original baseline: 500500

    • Calculation: 100500×100%=20%\frac{100}{500} \times 100\% = 20\%

  3. Work backward from final amounts by dividing by the multiplier. 

    Example: A shirt costs $36\$36 after a 20%20\% discount. What was the original price?

    • Discount multiplier: 1−0.20=0.801 - 0.20 = 0.80

    • Equation: 0.80×Original=360.80 \times \text{Original} = 36

    • Original price: 360.80=$45\frac{36}{0.80} = \$45

  4. Do not add successive percentages together; multiply their corresponding scaling factors. 

    Example: A stock goes up by 50%50\% on day one and down by 50%50\% on day two. What is the net change?

    • Combined multiplier: (1+0.50)×(1−0.50)=1.50×0.50=0.75(1 + 0.50) \times (1 - 0.50) = 1.50 \times 0.50 = 0.75

    • Net effect: 0.75−1=−0.25  ⟹  25% decrease overall0.75 - 1 = -0.25 \implies 25\% \text{ decrease overall}.

  5. Use 100100 as a convenient starting value for problems with unknown initial totals.

    Example: A price increases by 20%20\%, then decreases by 15%15\%. What is the net percent change?

    • Start with hypothetical base: $100\$100

    • After 20%20\% increase: 100×1.20=$120100 \times 1.20 = \$120

    • After 15%15\% decrease: 120×0.85=$102120 \times 0.85 = \$102

    • Net change: $102−$100=2% overall increase\$102 - \$100 = 2\% \text{ overall increase}.

Practice questions

00:00
Question 1 · easy
A box contains 300300 marbles, and 6060 of them are red. What percent of the marbles are red?
Question 2 · easy
In a survey, 18%18\% of the respondents said they prefer tea over coffee. If 4545 respondents prefer tea, how many total respondents were surveyed?
Question 3 · easy
The expression 0.75x0.75x represents the result of decreasing a positive quantity xx by what percent?
Question 4 · easy
The expression 1.12x1.12x represents the result of increasing a positive quantity xx by what percent?
Question 5 · easy
A nutrition label states that each serving of a granola bar provides 8%8\% of an adult's daily allowance of fiber. If pp percent of the daily allowance is provided by xx servings, which equation expresses pp in terms of xx?
Question 6 · easy
YearMembers
20191,000
20201,250
The table shows the number of members of a hiking club in 2019 and 2020. What was the percent increase in membership from 2019 to 2020?
Question 7 · easy
A class has 180180 students, and 4545 of them are freshmen. What percent of the students are NOT freshmen?
Question 8 · easy
In a group of 200200 people, 25%25\% are managers. How many people in the group are NOT managers?
Question 9 · easy
The expression 0.60x0.60x represents the result of decreasing a positive quantity xx by what percent?
Question 10 · easy
15%15\% of a number is 3030. What is the number?