Math · Geometry and Trigonometry

Lines, angles, and triangles

Explanation

Lines, angles, and triangles form the geometric foundation of the SAT, covering parallel line properties, angle relationships, and geometric properties of triangles.

Lines and Angles

When two parallel lines are intersected by a transversal line, specific angle relationships are created:

  • Adjacent Angles on a Line: Angles that lie on a straight line add up to 180∘180^\circ.

    Example: If ∠A\angle A and ∠B\angle B form a line and ∠A=70∘\angle A = 70^\circ, then ∠B=180∘−70∘=110∘\angle B = 180^\circ - 70^\circ = 110^\circ.

  • Vertical Angles: Opposite angles formed by two intersecting lines are always equal.

    Example: If two lines intersect to form opposite angles x∘x^\circ and 45∘45^\circ, then x=45∘x = 45^\circ.

  • Parallel Lines Cut by a Transversal:

    • Corresponding Angles: Equal to each other (e.g., top-left matches top-left).

    • Alternate Interior Angles: Equal to each other (e.g., inside angles on opposite sides of the transversal).

    • Same-Side Interior Angles: Supplementary (add up to 180∘180^\circ).

Triangle Fundamentals and Special Triangles

The interior angles of any triangle always add up to 180∘180^\circ.

  • Angle-Side Relationships:

    • Isosceles Triangle: Has 22 equal sides and 22 equal angles opposite those sides.

    • Equilateral Triangle: Has 33 equal sides and 33 equal angles (60∘60^\circ each).

  • Exterior Angle Theorem: The measure of an exterior angle of a triangle equals the sum of its two remote interior angles.

    Example: For △ABC\triangle ABC, an exterior angle at vertex CC equals ∠A+∠B\angle A + \angle B.

  • Similar Triangles: Triangles with equal corresponding angles have proportional side lengths.

    Example: If △ABC∼△DEF\triangle ABC \sim \triangle DEF with a scale factor of 22, then every side in △DEF\triangle DEF is twice as long as the corresponding side in △ABC\triangle ABC.

Right Triangles and Trigonometry

Right triangles (90∘90^\circ angle) follow the Pythagorean theorem: a2+b2=c2a^2 + b^2 = c^2, where cc is the hypotenuse.

Special Right Triangles

Triangle TypeAngle RatiosSide Length Ratios
45∘−45∘−90∘45^\circ-45^\circ-90^\circ45∘:45∘:90∘45^\circ : 45^\circ : 90^\circx:x:x2x : x : x\sqrt{2}
30∘−60∘−90∘30^\circ-60^\circ-90^\circ30∘:60∘:90∘30^\circ : 60^\circ : 90^\circx:x3:2xx : x\sqrt{3} : 2x

Example 1

mnt(3x+10)°(3x+10)°(2x+15)°(2x+15)°
In the figure, line mm is parallel to line nn, and both are cut by transversal tt. One angle formed measures (3x+10)∘(3x+10)^\circ, and a same-side interior angle formed with line nn measures (2x+15)∘(2x+15)^\circ. What is the value of xx? Note: Figure not drawn to scale.
A
55
B
1313
C
3131
D
4141
Choice C is correct. Same-side interior angles formed by a transversal cutting two parallel lines are supplementary, so (3x+10)+(2x+15)=180(3x+10)+(2x+15)=180. Combining like terms gives 5x+25=1805x+25=180, so 5x=1555x=155 and x=31x=31. Choice A is incorrect; it results from setting the two angle expressions equal to each other, 3x+10=2x+153x+10=2x+15, as though they were congruent rather than supplementary. Choice B is incorrect; it results from mistakenly treating the two angles as complementary (summing to 90∘90^\circ) instead of supplementary. Choice D is incorrect; it results from an arithmetic slip of adding instead of subtracting when isolating 5x5x, as in 5x+25=180⇒5x=2055x+25=180 \Rightarrow 5x=205.

Example 2

ABCD48°65°?
In the figure, △ABC\triangle ABC is shown with point DD on the extension of side BC‾\overline{BC} beyond CC, so that ∠ACD\angle ACD is an exterior angle of the triangle. The measure of angle AA is 48∘48^\circ and the measure of angle BB is 65∘65^\circ. What is the measure, in degrees, of ∠ACD\angle ACD? Note: Figure not drawn to scale.
A
65∘65^\circ
B
67∘67^\circ
C
113∘113^\circ
D
132∘132^\circ
Choice C is correct. By the Exterior Angle Theorem, the measure of an exterior angle of a triangle equals the sum of the two remote interior angles, so m∠ACD=m∠A+m∠B=48+65=113m\angle ACD = m\angle A + m\angle B = 48+65=113. Choice A is incorrect; this is the measure of angle BB alone, not the sum of both remote interior angles. Choice B is incorrect; this is the interior angle at CC (found from 180−48−65=67180-48-65=67), not the exterior angle, which is its supplement. Choice D is incorrect; it results from computing 180−48=132180-48=132 and ignoring angle BB entirely.

Tips for solving

  1. Use special right triangle ratios to skip using the Pythagorean theorem.

    Example: A 30∘−60∘−90∘30^\circ-60^\circ-90^\circ triangle has a shorter leg (xx) of 55. What are the other sides?

    SideRatio FormulaValue
    Short Leg (30∘30^\circ)xx55
    Long Leg (60∘60^\circ)x3x\sqrt{3}535\sqrt{3}
    Hypotenuse (90∘90^\circ)2x2x1010

  2. Apply the Exterior Angle Theorem for quick mental math on triangle problems.

    Example: A triangle has interior angles of 50∘50^\circ and 60∘60^\circ. Find the exterior angle at the third vertex.

    MethodStepsCalculation
    Standard MethodFind 3rd angle, then subtract from 180∘180^\circ180−(50+60)=70  ⟹  180−70=110∘180 - (50 + 60) = 70 \implies 180 - 70 = 110^\circ
    Exterior Angle RuleSum the two remote interior angles directly50∘+60∘=110∘50^\circ + 60^\circ = 110^\circ

  3. Set up proportions between corresponding sides of similar triangles.

    Example: △ABC∼△DEF\triangle ABC \sim \triangle DEF. Side AB=6AB = 6, BC=8BC = 8, and corresponding side DE=9DE = 9. Find EFEF.

    StepProportional SetupCalculation
    Set RatioABDE=BCEF\frac{AB}{DE} = \frac{BC}{EF}69=8EF\frac{6}{9} = \frac{8}{EF}
    Cross-Multiply6⋅EF=726 \cdot EF = 72EF=726=12EF = \frac{72}{6} = 12

Practice questions

00:00
Question 1 · easy
jjkktt72°72°??
In the figure, line jj is parallel to line kk, and line tt is a transversal that intersects both lines. One angle formed at the intersection with line jj measures 72∘72^\circ and is corresponding to an angle formed at the intersection with line kk. What is the measure, in degrees, of that corresponding angle? Note: Figure not drawn to scale.
Question 2 · easy
ppqqrr115°115°x°x°
In the figure, lines pp and qq are parallel and are cut by transversal rr. One angle formed measures 115∘115^\circ, and a second angle, which is same-side interior with the first, measures x∘x^\circ. What is the value of xx? Note: Figure not drawn to scale.
Question 3 · easy
AABBCC50°50°65°65°??
In △ABC\triangle ABC, the measure of angle AA is 50∘50^\circ and the measure of angle BB is 65∘65^\circ. What is the measure, in degrees, of angle CC?
Question 4 · easy
DDFFEE38°38°??97°97°
In the figure, △DEF\triangle DEF has m∠D=38∘m\angle D=38^\circ and m∠E=97∘m\angle E=97^\circ. What is m∠Fm\angle F? Note: Figure not drawn to scale.
Question 5 · easy
73°73°41°41°??BBCCAADD
In the figure, ∠BCD\angle BCD is an exterior angle of △ABC\triangle ABC at vertex CC. The measure of angle AA is 41∘41^\circ and the measure of angle BB is 73∘73^\circ. What is the measure, in degrees, of ∠BCD\angle BCD? Note: Figure not drawn to scale.
Question 6 · easy
58°58°??132°132°JJLLKKNN
In the figure, the exterior angle of △JKL\triangle JKL at vertex LL measures 132∘132^\circ. The measure of angle JJ is 58∘58^\circ. What is the measure, in degrees, of angle KK? Note: Figure not drawn to scale.
Question 7 · easy
PPQQRR63°63°??
In isosceles △PQR\triangle PQR, side PQ‾\overline{PQ} is congruent to side PR‾\overline{PR}. The measure of angle QQ is 63∘63^\circ. What is the measure, in degrees, of angle RR?
Question 8 · easy
SSTTUU84°84°VVWWXX??
Triangles STUSTU and VWXVWX are congruent, where SS, TT, and UU correspond to VV, WW, and XX, respectively. The measure of angle TT is 84∘84^\circ. What is the measure of angle WW?
Question 9 · easy
AABBCC6688DDEEFF99??
In the figure, △ABC∼△DEF\triangle ABC \sim \triangle DEF, where AA, BB, CC correspond to DD, EE, FF, respectively. Side AB‾\overline{AB} has length 66, side DE‾\overline{DE} has length 99, and side BC‾\overline{BC} has length 88. What is the length of side EF‾\overline{EF}?
Question 10 · easy
AABBCCDDEE442266??
In the figure, DE‾\overline{DE} is parallel to BC‾\overline{BC}, with DD on AB‾\overline{AB} and EE on AC‾\overline{AC}, so that △ADE∼△ABC\triangle ADE \sim \triangle ABC. If AD=4AD=4, DB=2DB=2, and AE=6AE=6, what is the length of EC‾\overline{EC}? Note: Figure not drawn to scale.